Model 4 Train Vs Pole/Signal Post/Man Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CPO S.I.2006]

A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is

a) 15 sec

b) 18 sec

c) 20 sec

d) 10 sec

Answer: (c)

Using Rule 5,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t

Relative speed of train

= (36 - 9) kmph = 27 kmph

= ${27 × 5}/18$ m/sec = $15/2$ m/sec

Required time

= $\text"Length of the train"/ \text"Relative speed"$

= ${150 × 2}/15 = 20$ seconds

Question : 7 [SSC CHSL 2015]

A train passes an electrical pole in 20 seconds and passes a platform 250 m long in 45 seconds. Find the length of the train.

a) 200m

b) 300m

c) 250m

d) 400m

Answer: (a)

Using Rule 1,

If the length of train be x metre, then speed of train

= $x/20 = {x + 250}/45$

$x/4 = {x + 250}/9$

9x = 4x + 1000

9x - 4x = 1000

5x = 1000

x = $1000/5$ = 200 metre

Question : 8 [SSC CGL Prelim 1999]

A train 180 m long moving at the speed of 20 m/sec. over-takes a man moving at a speed of 10m/ sec in the same direction. The train passes the man in :

a) 9 sec

b) 18 sec

c) 27 sec

d) 6 sec

Answer: (b)

Using Rule 5,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t

Relative speed of man and train

= 20 - 10 = 10m/sec.

Required time = $180/10$ = 18 seconds

Question : 9 [SSC CGL Tier-I 2016]

The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is

a) 9 seconds

b) 6 seconds

c) 4 seconds

d) 8 seconds

Answer: (d)

Distance covered in crossing a pole

= Length of train Speed of train = 72 kmph

= $({72 × 5}/18)$ m./sec. = 20 m./sec.

Required time = $160/20$ = 8 seconds

Question : 10 [SSC CGL Tier-I 2016]

In what time will a 100 metre long train running with a speed of 50 km/hr cross a pillar ?

a) 72 seconds

b) 7.2 seconds

c) 70 seconds

d) 7.0 seconds

Answer: (b)

Speed of train = 50 kmph

= $({50 × 5}/18)$ m./sec. = $125/9$ m./sec.

Required time = $({100/125}/9)$ seconds

= $({100 × 9}/125)$ = 7.2 seconds

IMPORTANT quantitative aptitude EXERCISES

Model 4 Train Vs Pole/Signal Post/Man Shortcuts »

Click to Read...

Model 4 Train Vs Pole/Signal Post/Man Online Quiz

Click to Start..

Recently Added Subject & Categories For All Competitive Exams

Mensuration Aptitude Practice Mcq Questions IBPS Clerk 2024

Most Important Practice Mensuration aptitude multiple choice questions, answers with detailed solutions, PDF beginner to advanced for IBPS Clerk Prelims 2024

11-May-2024 by Careericons

Continue Reading »

Top Clock Aptitude Questions and Answers PDF IBPS Clerk 2024

Recent Important IBPS Clerk Prelims 2024 Aptitude Clock MCQ Questions and answers with easy and logical explanation, PDF. Topic wise Free online practice test

10-May-2024 by Careericons

Continue Reading »

New Time and Distance Aptitude MCQ PDF for IBPS Clerk 2024

Latest Time and Distance multiple choice questions and answers with solution PDF for IBPS Clerk Prelims 2024. Practice Speed Aptitude based Objective Mcq

09-May-2024 by Careericons

Continue Reading »

Word Formation Objective Questions MCQs for IBPS Clerk 2024

Current year Important Objective Questions and Answers with Explanation for IBPS Clerk Prelims 2024 exam. English Vocabulary multiple choice practice exercises

08-May-2024 by Careericons

Continue Reading »